2x^2-160x+375=0

Solution for 2x^2-160x+375=0 equation:

2x^2-160x+375=0

a = 2; b = -160; c = +375;
Δ = b2-4ac
Δ = -1602-4·2·375
Δ = 22600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{22600}=\sqrt{100*226}=\sqrt{100}*\sqrt{226}=10\sqrt{226}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-160)-10\sqrt{226}}{2*2}=\frac{160-10\sqrt{226}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-160)+10\sqrt{226}}{2*2}=\frac{160+10\sqrt{226}}{4}
$